Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (2025)

Engage NY Eureka Math 4th Grade Module 5 Lesson 17 Answer Key

Eureka Math Grade 4 Module 5 Lesson 17 Problem Set Answer Key

Question 1.
Use the following three fractions to write two subtraction and two addition number sentences.
a. \(\frac{8}{5}\), \(\frac{2}{5}\), \(\frac{10}{5}\)

Answer:
Subtraction sentences = 7/5, 6/5, 1/5, -1/5, 9/5, 8/5.
Addition sentences = 9/5,10/5, 3/5, 4/5, 11/5, 12/5.

Explanation:
In the above-given question,
given that,
8/5, 2/5, 10/5.
8/5 + 1 = 9/5.
9/5 + 1 = 10/5.
2/5 + 1 = 3/5.
3/5 + 1 = 4/5.
10/5 + 1 = 11/5.
11/5 + 1 = 12/5.
8/5 – 1 = 7/5.
7/5 – 1 = 6/5.
2/5 – 1 = 1/5.
1/5 – 1 = -1/5.
10/5 – 1 = 9/5.
9/5 – 1 = 8/5.

b. \(\frac{15}{8}\), \(\frac{7}{8}\), \(\frac{8}{8}\)

Answer:
Subtraction sentences = 14/8, 13/8, 6/8, 5/8, 7/8, 6/8.
Addition sentences = 16/8,17/8, 8/8, 9/8, 9/8, 10/8.

Explanation:
In the above-given question,
given that,
15/8, 7/8, 8/8.
15/8 + 1 = 16/8.
16/8 + 1 = 17/8.
7/8 + 1 = 8/8.
8/8 + 1 = 9/8.
9/8 + 1 = 10/8.
10/8 + 1 = 11/8.
15/8 – 1 = 14/8.
14/8 – 1 = 13/8.
7/8 – 1 = 6/8.
6/8 – 1 = 5/8.
8/8 – 1 = -7/8.
7/8 – 1 = 6/8.

Question 2.
Solve. Model each subtraction problem with a number line, and solve by both counting up and subtracting. Part (a) has been completed for you.
a. 1 – \(\frac{3}{4}\)
Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (1)

Answer:
1 – 3/4 = 1/4.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 3/4.
4 – 3/4.
1/4.

b. 1 – \(\frac{8}{10}\)

Answer:
1 – 8/10 = 2/10.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 8/10.
10 – 8/10.
2/10.

c. 1 – \(\frac{3}{5}\)

Answer:
1 – 3/5 = 2/5.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 3/5.
5 – 3/5.
2/5.

d. 1 – \(\frac{5}{8}\)

Answer:
1 – 5/8 = 3/8.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 5/8.
8 – 5/8.
3/8.

e. 1\(\frac{2}{10}\) – \(\frac{7}{10}\)

Answer:
1 – 2/10 – 7/10 = 1/10.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 2/10.
10 – 2/10.
8/10 – 7/10.
1/10.

f. 1\(\frac{1}{5}\) – \(\frac{3}{5}\)

Answer:
1 – 1/5 – 3/5 = 1/5.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 1/5.
5 – 1/5.
4/5 – 3/5.
1/5.

Question 3.
Find the difference in two ways. Use number bonds to decompose the total. Part (a) has been completed for you.
a. Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (2)

Answer:
5/5 + 2/5 = 7/5.

Explanation:
In the above-given question,
given that,
1(2/5) – 4/5.
7/5 – 4/5 = 3/5.
5/5 + 2/5 = 7/5.
7/5 – 4/5 = 3/5.
5/5 – 4/5 = 1/5.
1/5 + 2/5 = 3/5.

b. 1\(\frac{3}{6}\) – \(\frac{4}{6}\)

Answer:
6/6 + 3/6 = 9/6.

Explanation:
In the above-given question,
given that,
1(3/6) – 4/6.
9/6 – 4/6 = 5/6.
6/6 + 3/6 = 9/6.
9/6 – 4/6 = 5/6.
6/6 – 4/6 = 2/6.
2/6 + 3/6 = 5/6.
Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (3)

c. 1\(\frac{6}{8}\) – \(\frac{7}{8}\)

Answer:
10/8 + 4/8 = 14/8.

Explanation:
In the above-given question,
given that,
1(6/8) – 7/8.
14/8 – 7/8 = 7/8.
10/8 + 4/8 = 14/8.
14/8 – 7/8 = 7/8.
10/8 – 7/8 = 3/8.
3/8 + 4/8 = 7/8.
Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (4)

d. 1\(\frac{1}{10}\) – \(\frac{7}{10}\)

Answer:
8/10 + 3/10 = 11/10.

Explanation:
In the above-given question,
given that,
1(1/10) – 7/10.
11/10 – 7/10 = 4/10.
8/10 + 3/10 = 11/10.
11/10 – 7/10 = 4/10.
8/10 – 7/10 = 2/10.
2/10 + 3/10 = 5/10.
Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (5)

e. 1\(\frac{3}{12}\) – \(\frac{6}{12}\)

Answer:
6/12 + 3/12 = 9/12.

Explanation:
In the above-given question,
given that,
1(3/12) – 9/12.
15/12 – 9/12 = 3/12.
7/12 + 8/12 = 15/12.
9/12 – 6/12 = 3/12.
6/12 – 6/12 = 0.
6/12 + 3/12 = 9/12.
Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (6)

Eureka Math Grade 4 Module 5 Lesson 17 Exit Ticket Answer Key

Question 1.
Solve. Model the problem with a number line, and solve by both counting up and subtracting.
1 – \(\frac{2}{5}\)

Answer:
1 – 2/5 = 3/5.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 2/5.
5 – 2/5.
3/5.

Question 2.
Find the difference in two ways. Use a number bond to show the decomposition.
1\(\frac{2}{7}\) – \(\frac{5}{7}\)

Answer:
5/7 + 4/7 = 9/7.

Explanation:
In the above-given question,
given that,
1(2/7) – 5/7.
9/7 – 5/7 = 4/7.
5/7 + 4/7 = 9/7.
9/7 – 5/7 = 4/7.
5/7 – 4/5 = 1/7.
1/7 + 2/7 = 3/7.

Eureka Math Grade 4 Module 5 Lesson 17 Homework Answer Key

Question 1.
Use the following three fractions to write two subtraction and two addition number sentences.

a. \(\frac{5}{6}\), \(\frac{4}{6}\), \(\frac{9}{6}\)

Answer:
Subtraction sentences = 4/6, 3/6, 3/6, 2/6, 8/6, 7/6.
Addition sentences = 6/6,7/6, 5/6, 6/6, 10/6, 11/6.

Explanation:
In the above-given question,
given that,
5/6, 4/6, 9/6.
5/6 + 1 = 6/6.
6/6 + 1 = 7/6.
4/6 + 1 = 5/6.
5/6 + 1 = 6/6.
9/6 + 1 = 10/6.
10/6 + 1 = 11/6.
5/6 – 1 = 4/6.
4/6 – 1 = 3/6.
4/6 – 1 = 3/6.
3/6 – 1 = 2/6.
9/6 – 1 = -8/6.
8/6 – 1 = 7/6.

b. \(\frac{5}{9}\), \(\frac{13}{9}\), \(\frac{8}{9}\)

Answer:
Subtraction sentences = 4/9, 3/9, 12/9, 11/9, 7/9, 6/9.
Addition sentences = 6/9,7/9, 14/9, 15/9, 9/9, 10/9.

Explanation:
In the above-given question,
given that,
5/9, 13/9, 8/9.
5/9 + 1 = 6/9.
6/9 + 1 = 7/9.
13/9 + 1 = 14/9.
14/9 + 1 = 15/9.
8/9 + 1 = 9/9.
9/9 + 1 = 10/9.
5/9 – 1 = 4/9.
4/9 – 1 = 3/9.
13/9 – 1 = 12/9.
12/9 – 1 = 11/9.
8/9 – 1 = 7/9.
7/9 – 1 = 6/9.

Question 2.
Solve. Model each subtraction problem with a number line, and solve by both counting up and subtracting.

a. 1 – \(\frac{5}{8}\)

Answer:
1 – 5/8 = 3/8.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 5/8.
8 – 5/8.
3/8.

b. 1 – \(\frac{2}{5}\)

Answer:
1 – 2/5 = 3/5.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 2/5.
5 – 2/5.
3/5.

c. 1\(\frac{3}{6}\) – \(\frac{5}{6}\)

Answer:
1 – 3/6 – 5/6 = -2/6.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 3/6.
6 – 3/6.
3/6 – 5/6.
-2/6.

d. 1 – \(\frac{1}{4}\)

Answer:
1 – 1/4 = 3/4.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 1/4.
4 – 1/4.
3/4.

e. 1\(\frac{1}{3}\) – \(\frac{2}{3}\)

Answer:
1 – 1/3 – 2/3 = 0.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 1/3.
3 – 1/3.
2/3 – 2/3.
0

f. 1\(\frac{1}{5}\) – \(\frac{2}{5}\)

Answer:
1 – 1/5 – 2/5 = 2/5.

Explanation:
In the above-given question,
given that,
Model each subtraction problem with a number line.
1 – 1/5.
5 – 1/5.
4/5 – 2/5.
2/5.

Question 3.
Find the difference in two ways. Use number bonds to decompose the total. Part (a) has been completed for you.
a. Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (7)

b. 1\(\frac{3}{8}\) – \(\frac{7}{8}\)

Answer:
8/8 + 3/8 = 11/8.

Explanation:
In the above-given question,
given that,
1(3/8) – 7/8.
11/8 – 7/8 = 4/8.
8/8 + 3/8 = 11/8.
11/8 – 7/8 = 4/8.
8/8 – 7/8 = 1/8.
1/8 + 3/8 = 4/8.
Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (8)

c. 1\(\frac{1}{4}\) – \(\frac{3}{4}\)

Answer:
8/10 + 3/10 = 11/10.

Explanation:
In the above-given question,
given that,
1(1/4) – 3/4.
5/4 – 3/4 = 2/4.
3/4 + 2/4 = 5/4.
5/4 – 3/4 = 2/4.
3/4 – 3/4 = 0.
0 + 2/4 = 2/4.
Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (9)

d. 1\(\frac{2}{7}\) – \(\frac{5}{7}\)

Answer:
6/7 + 3/7 = 9/7.

Explanation:
In the above-given question,
given that,
1(2/7) – 5/7.
9/7 – 2/7 = 7/7.
6/7 + 3/7 = 9/7.
9/7 – 2/7 = 7/7.
6/7 – 2/7 = 4/7.
4/7 + 3/7 = 7/7.
Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (10)

e. 1\(\frac{3}{10}\) – \(\frac{7}{10}\)

Answer:
8/10 + 3/10 = 11/10.

Explanation:
In the above-given question,
given that,
1(3/10) – 7/10.
13/10 – 7/10 = 6/10.
7/10 + 6/10 = 13/10.
13/10 – 7/10 = 6/10.
7/10 – 7/10 = 0.
0 + 6/10 = 6/10.
Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (11)

Eureka Math Grade 4 Module 5 Lesson 17 Answer Key (2025)

FAQs

What grade does Eureka math go up to? ›

Eureka Math® is a holistic Prekindergarten through Grade 12 curriculum that carefully sequences mathematical progressions in expertly crafted modules, making math a joy to teach and learn. We provide in-depth professional development, learning materials, and a community of support.

What are the four core components of a Eureka Math TEKS lesson? ›

A typical Eureka lesson is comprised of four critical components: fluency practice, concept development (including a problem set), application problem, and student debrief (including the Exit Ticket).

What is the purpose of the concept development in Eureka math? ›

The concept development is generally comprised of carefully sequenced problems centered within a specific topic to begin developing mastery via gradual increases in complexity.

What is the hardest math grade? ›

The hardest math class you can take in high school is typically AP Calculus BC or IB Math HL. These courses cover a wide range of advanced mathematical concepts, including calculus, trigonometry, and statistics.

Is Eureka Math good or bad? ›

Is Eureka Math a good curriculum? The answer to this question depends on the target audience. If you're a teacher in a public school who needs to cover State Standards and your goal is merely to prepare students for State tests, then Eureka may be a good curriculum for you.

How long does an Eureka math lesson take? ›

Not all Eureka Math lessons are formatted in the same way, but lessons in the same grade-band all follow a similar structure. Lessons in A Story of Units (PK-5) are written for a 60-minute class period, except for Pre-K lessons, which are 25 minutes, and K lessons, which are 50 minutes*.

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Explore how the TEKS are organized by Introduction, Knowledge and Skill Statement, Strand, and Student Expectations across a grade level or course. Recognize and differentiate between cognitive and content expectations noted in the TEKS.

Is Eureka math the same as common core? ›

Eureka Math, a Common Core-aligned curriculum published by the non-profit Great Minds Inc., equates mathematical concepts to stories, with the aim of developing conceptual understanding.

Who is the father of math Eureka? ›

Here's a closer look into this sudden discovery (the “Eureka!” moment): The famous Greek mathematician, physicist, and astronomer, Archimedes was born in 287 BC in Syracuse, a Greek colony in Sicily (an island now part of Italy).

Who created Eureka Math? ›

Together, these two math resources are the most commonly used in US schools. Working with educators and experts, Great Minds PBC has also developed Eureka Math 2™, Wit & Wisdom® ELA, Geodes® books for emerging readers, and PhD Science®.

What are the goals of Eureka Math? ›

Eureka Math is designed to support students in gaining a solid understanding of concepts, a high degree of procedural skill and fluency, and the ability to apply math to solve problems in and outside the classroom. There is also an intentional coherence linking topics and thinking across grades.

What is the highest level of math in 9th grade? ›

9th grade math usually focuses on Algebra I, but can include other advanced mathematics such as Geometry, Algebra II, Pre-Calculus or Trigonometry.

What is the hardest math in 5th grade? ›

Some of the hardest math problems for fifth graders involve multiplying: multiplying using square models, multiplying fractions and whole numbers using expanded form, and multiplying fractions using number lines.

What is advanced math in 8th grade called? ›

Almost every school district in the state offers an accelerated math option for selected students. These students take Algebra I in 8th grade. These students complete Algebra II, Geometry and Precalculus one year earlier than their peers. This allows them to take AP Calculus A/B in their senior year.

What grade level is go math for? ›

Go Math! (K-6) on Ed is an easy-to-implement core curriculum with an effective instructional approach that includes robust differentiation and assessment resources that engage all levels of learners and support all levels of teachers, from novice to master.

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